What is Dy/dx Z^omg = F J00 * Dpwn/dx?
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reads dy dx of z to the omg equals f sub j00 times d pwn dx.
The new derivative formula. Bish.
please take dy/dx of 563210983x^32 * ln(sin(32x*y*z) * tan^-1(q)
The answer is 42. Bish.
I cite dy/dx z^omg = f (sub) j00 * dpwn/dx
See
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It's used b/c technically, you're not swearing,..
